Impulse, linear momentum, conservation of momentum, and collisions
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Momentum provides a second powerful conservation law alongside energy, and for many collision and explosion problems it is the most direct route to a solution. Linear momentum, defined as the product of an object's mass and velocity (p = mv), is a vector quantity that captures both how massive an object is and how fast it is moving. The impulse-momentum theorem states that the net force acting over a time interval equals the change in momentum: J = F_net Δt = Δp. This theorem explains why airbags and crumple zones save lives—they increase the duration of a collision, which reduces the peak force for the same momentum change. The cornerstone of the unit is the law of conservation of linear momentum: if the net external force on a system is zero, the total momentum of that system remains constant. This holds true even when mechanical energy is not conserved, such as in perfectly inelastic collisions where objects stick together. You must distinguish between elastic collisions, where both momentum and kinetic energy are conserved, and inelastic collisions, where only momentum is conserved. In two-dimensional collisions, momentum is conserved independently along each perpendicular axis, requiring you to break velocities into components and write separate conservation equations for x and y. The unit also introduces the center of mass of a system, which moves as if all external forces were applied at that single point and all mass were concentrated there. For a two-object system, the center of mass velocity remains constant in the absence of external forces, a fact that often simplifies complex collision analyses. AP Exam questions frequently present ballistic pendulums, exploding projectiles, or skaters pushing off from each other, testing whether you can apply momentum conservation correctly while respecting its vector nature. Success depends on drawing clear before-and-after diagrams, labeling velocities as vectors, and never assuming a collision is elastic unless explicitly told so.
p = m*vJ = F_net * Δt = Δpm1*v1 + m2*v2 = m1*v1' + m2*v2' (conservation of momentum)v1 - v2 = -(v1' - v2') (relative velocity, elastic only)x_cm = (m1*x1 + m2*x2) / (m1 + m2)v_cm = (m1*v1 + m2*v2) / (m1 + m2)Answer each question one at a time. Click an option to select your answer.
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Quick reference for Momentum. Print this out and review before the exam!
p = m*vJ = Δp = F_avg * ΔtΣp_before = Σp_after (isolated system)m1*v1 + m2*v2 = m1*v1' + m2*v2'v1 - v2 = -(v1' - v2') (elastic)x_cm = Σ(m_i*x_i) / Σm_iv_cm = Σ(m_i*v_i) / Σm_i