Coulomb's law, electric fields, and electric potential
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This unit introduces the fundamental principles of electrostatics, which govern the behavior of stationary electric charges. You begin with the concept of electric charge itself—quantized, conserved, and coming in two varieties: positive and negative. Like charges repel, opposite charges attract, and the magnitude of this force is described by Coulomb's Law: F = k|q₁q₂|/r². This inverse-square law is structurally identical to Newton's law of gravitation, but electric forces can be attractive or repulsive and are generally much stronger. The electric field E extends the idea of force by defining the force per unit positive test charge: E = F/q. Electric field lines provide a visual representation, originating on positive charges and terminating on negative charges, with density indicating field strength. You must be able to calculate the electric field due to one or more point charges using vector superposition. The scalar electric potential V, measured in volts, represents electric potential energy per unit charge. While electric field is a vector that tells you the force direction, potential is a scalar that tells you how much energy a charge would have at a point. The two are related by E = −ΔV/Δx in one dimension; field points in the direction of steepest potential decrease. Equipotential surfaces are perpendicular to field lines and represent regions where no work is required to move a charge. You will also study the behavior of conductors in electrostatic equilibrium: the electric field inside a conductor is zero, all excess charge resides on the surface, and the surface is an equipotential. Insulators, by contrast, do not allow free charge movement. On the AP Exam, this unit is tested with both quantitative calculations and conceptual questions about field line patterns, potential maps, and the behavior of charges near conductors. Mastering the distinction between vector field and scalar potential is essential for every subsequent topic in electricity and magnetism.
F = k * |q1*q2| / r² (Coulomb's Law)E = k * |q| / r² (point charge field)E = F / q_testV = k * q / r (point charge potential)U_E = k * q1*q2 / rW = -ΔU_E = q * ΔVE_x = -dV/dxk = 8.99×10⁹ N·m²/C²Answer each question one at a time. Click an option to select your answer.
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Quick reference for Electric Force, Field, and Potential. Print this out and review before the exam!
F = k * |q1*q2| / r² (Coulomb's Law)E = k * |q| / r² (point charge field)E = F / q_testV = k * q / r (point charge potential)U_E = k * q1*q2 / rW = -ΔU_E = q * ΔVE_x = -dV/dxk = 8.99×10⁹ N·m²/C²Download official review materials for this unit.
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